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7r^2-37r+10=0
a = 7; b = -37; c = +10;
Δ = b2-4ac
Δ = -372-4·7·10
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-33}{2*7}=\frac{4}{14} =2/7 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+33}{2*7}=\frac{70}{14} =5 $
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